1996 United States presidential election in Alaska

1996 United States presidential election in Alaska
Dole 40–50% 50–60% 60–70%	Clinton 30–40% 40–50% 50–60%
President before election; Bill Clinton; Democratic	Elected President ; Bill Clinton; Democratic

The 1996 United States presidential election in Alaska took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose representatives, or electors to the Electoral College, who voted for president and vice president.

Alaska was won by Senator Bob Dole (R-KS), with Dole winning 50.80% to 33.27% over President Bill Clinton (D) by a margin of 17.53%.^[1] Billionaire businessman Ross Perot (Reform-TX) finished in third, with 10.9% of the popular vote.

With 50.8% of the popular vote, Alaska proved to be Dole's fifth strongest state in the 1996 election after Utah, Kansas, Nebraska and Idaho.^[2]

Results

1996 United States presidential election in Alaska
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Republican	Robert Dole	Jack Kemp	122,746	50.80%	3
	Democratic	Bill Clinton (incumbent)	Al Gore (incumbent)	80,380	33.27%	0
	Reform	Ross Perot	Patrick Choate	26,333	10.90%	0
	Green Party	Ralph Nader	Winona LaDuke	7,597	3.14%	0
	Libertarian	Harry Browne	Jo Jorgensen	2,276	0.94%	0
	U.S. Taxpayers' Party	Howard Phillips	Herbert Titus	925	0.38%	0
	Natural Law	John Hagelin	Mike Tompkins	729	0.30%	0
	Write-ins			634	0.26%	0
Totals				241,620	100.0%	3